The angle of triangle measures x + 110 degrees x + 20° and x Plus 30° find the measure of the smallest angle a 70° B 40° c 50° d 60°

1 answer

To find the smallest angle, we need to compare the three given angles and determine which one has the smallest measure.

Given: Angle 1 = x + 110°, Angle 2 = x + 20°, Angle 3 = x + 30°

To compare the angles, we can set up an inequality:

x + 110° < x + 20° < x + 30°

Simplifying, we have:

110° < 20° < 30°

This is not a true statement, as 110° is greater than both 20° and 30°. Therefore, this inequality does not hold.

We can try another approach by setting up a different inequality:

x + 110° > x + 20° > x + 30°

Simplifying and comparing, we get:

110° > 20° > 30°

This is a true statement. Therefore, the measure of the smallest angle is x + 30°.

Since we do not have a specific value for x, we cannot determine the exact measure of the smallest angle. However, we can still eliminate options:

a) 70°: This cannot be the measure of the smallest angle since x + 30° will be less than 70° if x is positive.
b) 40°: This can be the measure of the smallest angle if x = 10.
c) 50°: This cannot be the measure of the smallest angle. If x = 20, then the smallest angle would be x + 30° = 50°.
d) 60°: This cannot be the measure of the smallest angle since x + 30° will be less than 60° if x is positive.

Therefore, the measure of the smallest angle is 40° (option b).