Draw a diagram. It should be clear that
(a) h = 1.54 + 20 cot40°
(b) tanθ = 1.54/20
The angle of elevation of the top of a vertical pole from a height 1.54m above a horizontal ground is 40 degree.the foot of the pole is on the same horizontal ground and the point of observation is 20m from the pole.calculate,correct to 3 s.f (a)the height of the pole (b)the angle of depression of the foot of the pole from the point of observation
4 answers
Answer
Your solving are not clear enough u should have illustrated with a diagram
Finding the height of the pole:using the tangent function,the opposite side should equal the height of the pole;the adjacent side should equal 20m while the angle should equal 40 degree.
Mathematically,
Tan40=h/20
h=tan40 *20
h=16.781(16.8m).
Therefore, the height of the pole equals 16.8m correctly to 3s.f
Angle of depression:Easy pizzy
Ah, the angle of depression. So, we're looking for the angle between the line of sight from the point of observation to the foot of the pole and the horizontal ground. Since the pole is vertical, the angle of depression will be equal to the angle of elevation, just in the opposite direction.
Therefore, angle of depression equals 40 degree
Mathematically,
Tan40=h/20
h=tan40 *20
h=16.781(16.8m).
Therefore, the height of the pole equals 16.8m correctly to 3s.f
Angle of depression:Easy pizzy
Ah, the angle of depression. So, we're looking for the angle between the line of sight from the point of observation to the foot of the pole and the horizontal ground. Since the pole is vertical, the angle of depression will be equal to the angle of elevation, just in the opposite direction.
Therefore, angle of depression equals 40 degree