Make your sketch.
I labelled the top of the building P and its bottom Q, the top of the pole A and its bottom B.
So QA = 145 m
Enter all the given angles, after that all angles at A and B can be found
In triangle PQB , angle PBQ = 34° and
tan 34 = PQ/145
PQ = ..... <----- the height of the building
Using cos 34 = 145/PB , you can find PB
In triangle ABP, you know all the angles, and the side PB
Use the sine law to find AB
the angle of depression of the top and the foot of a flagpole as seen from the top of a building145 metres away are 26 degree and 34 degree respectively .find the heights of pole and the building?
5 answers
h1 = ht. of flagpole.
h2 = distance from top of flagpole to top of bldg.
(h1+h2) = ht. of bldg.
Tan34 = (h1+h2)/145.
(h1+h2) =145*Tan34 = 98 m. = ht. of bldg.
Tan26 = h2/145.
h2 = 145*Tan26 = 71 m.
h1 = (h1+h2) - h2 = 98 - 71 = 27 m. = ht. of flagpole.
h2 = distance from top of flagpole to top of bldg.
(h1+h2) = ht. of bldg.
Tan34 = (h1+h2)/145.
(h1+h2) =145*Tan34 = 98 m. = ht. of bldg.
Tan26 = h2/145.
h2 = 145*Tan26 = 71 m.
h1 = (h1+h2) - h2 = 98 - 71 = 27 m. = ht. of flagpole.
thank you give me this chance to
Compete international students.I am originally from Ethiopia .I am a grade 10 students.now Ethiopia difficult to learn b/c of many reasons so i want to go canada
Compete international students.I am originally from Ethiopia .I am a grade 10 students.now Ethiopia difficult to learn b/c of many reasons so i want to go canada
I dont know the answer.
I dont know the answer.uhhhhhhhhhhhhhh