tanØ = y/x
since tanØ = -3/5 and you are in II
then y = 3, and x = -5 , or in that ratio
now look at C) with point (-10,6)
isn't tanØ = 6/-10 = -3/5 ??
It said "possible point", other points could have been
(-20,12), (-200, 120) etc
(in your diagram, the end point in II should have been (-5,3) , not (-5,-3) )
The angle θ is in the second quadrant and tan θ = -3/5. Point P is on the terminal arm of angle θ/ Which is a possible coordinate for P?
A) (-5,√29)
B) (-3,√29)
C) (-10,6)
D) (-6,10)
I drew the triangle, and aren't the coordinates supposed to be (-5,-3)? However the answer is C, I don't get it, can someone please explain?
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