The amplitude of a sound wave is measured in terms of its maximum gauge pressure. By what factor does the amplitude of a sound wave increase if the sound level goes up by 38.0 dB?

Answer 1

ΔL= L₁ - L₂ =
=10 log₁₀(I₁/I₀) – 10log₁₀(I₂/I₀) =
=10 log₁₀(I₁/I₂)
ΔL/10 = log₁₀(I₁/I₂)
I∼A²
A₁/A₂=sqrt{ I₁/I }=sqrt{10^( ΔL/10)} =
=sqrt{10^( 38/10)} =79.4