To express the function \( Q(t) = 7300(1.1)^{2t + 2} \) in the form \( Q(t) = ab^t \), we can manipulate the original equation.
-
First, factor out the constant term: \[ Q(t) = 7300(1.1)^{2t + 2} \]
-
We can rewrite \( (1.1)^{2t + 2} \) as: \[ (1.1)^{2t + 2} = (1.1)^{2t} \cdot (1.1)^{2} = (1.1^2)^{t} \cdot (1.1^{2}) \]
-
Now, calculate \( 1.1^{2} \): \[ 1.1^{2} = 1.21 \]
-
Therefore, we can now write: \[ Q(t) = 7300 \cdot 1.21^{t} \cdot 1.1^{2} \]
-
Which simplifies to: \[ Q(t) = 7300 \times 1.21 \times (1.1^2)^{t} \] Here, you have \( a = 7300 \times 1.21 \) and \( b = 1.1^{2} \).
-
Finally, calculate \( a \): \[ a = 7300 \times 1.21 = 8833 \]
So now we have: \[ Q(t) = 8833(1.1^2)^{t} = 8833(1.21)^{t} \]
Thus, the equivalent function in the required form is:
\[ Q(t) = 8833(1.21)^{t} \]