The amount of heat needed to raise 25 g of a substance by 15°C is 293 J.

Question

What is the specific heat of the substance?

Use the equation C = q/mΔT .

Question 6 options:

0.13 J/g-°C

0.20 J/g-°C

0.46 J/g-°C

0.78 J/g-°C

Answer 1

To find the specific heat of the substance, we can rearrange the equation C = q/mΔT to solve for C:

C = q / (mΔT)

C = 293 J / (25 g * 15°C)

C = 293 J / (375 g*°C)

C = 0.78 J/g-°C

Therefore, the specific heat of the substance is 0.78 J/g-°C.