10.85 kcal/g x 1.3 pounds x (454 g/pound) = ?? kcal.
??kcal = mass H2O x specific heat water x (Tfinal - Tinitial)
Solve for Tfinal.
The amount of energy released by burning a fuel source, measured in energy per mass, is called fuel value. If all the energy obtained from burning 1.3 pounds of butane (fuel value 10.85 kcal/g) is used to heat 122 kg of water at an initial temperature of 20.9 degC, what is the final temperature?
3 answers
A gas at 65oC occupies 4.22 L At what Celsius temperature will the volume be 3.87 L assuming the same pressure?
(V1/T1) = (V2/T2)
T must be in Kelvin.
T must be in Kelvin.