Cu wire to Cu^2+ to Cu^+. Then, assuming acid conditions,
5Cu^+ + MnO4^- + 8H^+ --> Mn^+ + 5Cu^2+ + 4H2O
mols MnO4^- used = M x L = ?
mols Cu+ titrated = moles CuO = 5*moles MnO4^-
grams CuO = mols CuO x molar mass CuO
%CuO = (grams CuO/mass sample)*100 = ?
Post your work if you get stuck.
The amount of copper in a wire was determined by a redox titration using KMnO4 as the titrant. A 0.4185-g sample was dissolved in acid and the liberated Cu2+ quantitatively reduced to Cu+, using a reductor column. Titrating with 0.0250 M KMnO4 requires 41.27 mL to reach the endpoint. Determine the % w/w CuO in the sample of meteorite.
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