The amino acid serine is coded by the mRNA codon AGU. What is the base sequence of the DNA gene that originally produced this mRNA codon?(1 point)

Responses

AGU
AGU

TCA
TCA

UCA
UCA

TCC
TCC

1 answer

To find the base sequence of the DNA gene that would produce the mRNA codon AGU, we need to consider the rules of transcription, where RNA polymerase synthesizes RNA using one strand of the DNA as a template.

  1. The mRNA codon is AGU.
  2. The corresponding DNA template strand will be complementary to this mRNA sequence. In this case, adenine (A) pairs with thymine (T), uracil (U) in RNA corresponds to adenine (A) in DNA, and guanine (G) pairs with cytosine (C).

So, for the mRNA codon AGU:

  • A (A in DNA) corresponds to T (in DNA)
  • G (G in DNA) corresponds to C (in DNA)
  • U (U in mRNA corresponds to A in DNA)

Thus, the complementary DNA base sequence would be:

  • T (for A)
  • C (for G)
  • A (for U)

Putting that together: the DNA sequence is TCA.

Therefore, the answer is: TCA