The amino acid serine is coded by the mRNA codon AGU. What is the base sequence of the DNA gene that originally produced this mRNA codon?(1 point)

Responses

TCA
TCA

AGU
AGU

TCC
TCC

UCA

1 answer

To determine the base sequence of the DNA gene that would produce the mRNA codon AGU, we must first identify the corresponding DNA template strand sequence.

mRNA is synthesized from the DNA template strand through the process of transcription, where the DNA sequence is complementary to the mRNA sequence. The mRNA codon AGU would have been transcribed from the DNA sequence that is complementary to it.

The RNA base pairs as follows:

  • Adenine (A) pairs with Thymine (T) in DNA
  • Uracil (U) in RNA pairs with Adenine (A) in DNA
  • Guanine (G) pairs with Cytosine (C) in both RNA and DNA
  • Cytosine (C) pairs with Guanine (G) in both RNA and DNA

The mRNA codon AGU can be analyzed as follows:

  • A (Adenine) pairs with T (Thymine)
  • G (Guanine) pairs with C (Cytosine)
  • U (Uracil) pairs with A (Adenine in DNA)

Thus, the corresponding DNA sequence would be:

  • A (mRNA) = T (DNA)
  • G (mRNA) = C (DNA)
  • U (mRNA) = A (DNA)

Putting this together, the DNA sequence complementary to the mRNA codon AGU is TCA.

Therefore, the correct response is: TCA