The amino acid serine is coded by the mRNA codon AGU. What is the base sequence of the DNA gene that originally produced this mRNA codon?(1 point)

Question

Responses

TCA
TCA

AGU
AGU

UCA
UCA

TCC

Answer 1

To determine the base sequence of the DNA gene that originally produced the mRNA codon AGU, we need to consider how DNA is transcribed into mRNA.

The mRNA codon AGU corresponds to the following complementary DNA sequence. Since RNA uses uracil (U) instead of thymine (T), the process goes as follows:

1. Replace A in RNA with T in DNA.
2. Replace U in RNA with A in DNA.
3. Replace G in RNA with C in DNA.

Thus, the mRNA codon AGU would be transcribed from the DNA sequence:

• A (in mRNA) is produced from T (in DNA)
• G (in mRNA) is produced from C (in DNA)
• U (in mRNA) is produced from A (in DNA)

So, the equivalent DNA sequence that would produce the mRNA codon AGU is TCA.

Final answer: TCA