The altitude of the regular quadrilateral prism is h=13 cm and lateral area is AL = 624 cm2. Find: 1) The Surface Area of the prism; 2) The Volume of the prism.
Answer:
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AL = 2(L*h) = 624cm^2.
2(L*13) = 624, L = 24cm.
Assuming the ends are square, W = h = 13 cm.
1. As = 2(L*W) + AL.
Or As = 2(L*W) + 2(L*h).
2. V = L*W*h.
2(L*13) = 624, L = 24cm.
Assuming the ends are square, W = h = 13 cm.
1. As = 2(L*W) + AL.
Or As = 2(L*W) + 2(L*h).
2. V = L*W*h.
The prism is regular, meaning its bases are squares, of side s. Now you know that
h=13
4sh = 624
So, s = 12
Now you can work out the rest.
h=13
4sh = 624
So, s = 12
Now you can work out the rest.
Correction:
1. As = 2(L*W) + 2(L*h) + 2(W*h).
1. As = 2(L*W) + 2(L*h) + 2(W*h).
AL = 2(W*h) + 2(L*h) = 624cm^2.
2(13*13) + 2(L*13) = 624,
338 + 26L = 624,
L = 11 m.
1. Assuming the ends are square, W = h = 13 m.
As = 2(L*W) + 2(L*h) + 2(W*h).
2. V = L*W*h.
2(13*13) + 2(L*13) = 624,
338 + 26L = 624,
L = 11 m.
1. Assuming the ends are square, W = h = 13 m.
As = 2(L*W) + 2(L*h) + 2(W*h).
2. V = L*W*h.
The surface area is equal to 912 cm.
The volume is equal to 1872 cm.
The volume is equal to 1872 cm.
The prism is regular, which means that its bases are squares, of side v. Now you know that:
height=13
4 slant height = 624
So, side v = 12
You can now figure out that
SA (Surface area) = 912cm
Volume = 1872 cm
height=13
4 slant height = 624
So, side v = 12
You can now figure out that
SA (Surface area) = 912cm
Volume = 1872 cm
actually L = 6 because 6 x 13 x 24 = 1872cm cubed which his the volume i also go the answer right on my hw
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