The altitude (i.e., height) of a triangle is increasing at a rate of 2 cm/minute while the area of the triangle is increasing at a rate of 4 square cm/minute. At what rate is the base of the triangle changing when the altitude is 10.5 centimeters and the area is 97 square centimeters?

Answer 1

a = bh/2
da/dt = 1/2 (h db/dt + b dh/dt)

Now just plug and chug, solving for db/dt