The aircraft is coming in for landing, and has its flaps extended. The air pressure at the airport is 101325.0 Pa, but due to an exceptionally hot summer, the air temperature has risen to 40C.

Calculate the stall speed of the aircraft in these conditions, in kts.
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Engines
The jet engines of the aircraft have an inlet diameter of 2.96m. Furthermore, the aircraft is flying at a True Airspeed of 486 kts and the total thrust provided by the engines is 400 kN (which are not the correct answers to the previous questions). The aircraft is still flying at FL280.

Calculate the air flow per engine at this altitude (in kg/s).

Calculate the exhaust/jet velocity of the engines (in m/s).

Calculate the jet efficiency of those engines in percent. Don't include the % sign in your answer.

1 answer

To solve the problems you've presented, we'll break them down step by step.

Part 1: Calculate the Stall Speed of the Aircraft

To calculate stall speed, we can use the following formula:

\[ V_{\text{stall}} = \sqrt{\frac{2 \cdot W}{\rho \cdot S \cdot C_L}} \]

Where:

  • \( V_{\text{stall}} \) = stall speed (m/s)
  • \( W \) = weight of the aircraft (N)
  • \( \rho \) = air density (kg/m³)
  • \( S \) = wing area (m²)
  • \( C_L \) = lift coefficient (dimensionless)

Since we don't have all the required parameters like the weight of the aircraft or wing area, we can compute air density (\( \rho \)) using the ideal gas law:

\[ \rho = \frac{P}{R \cdot T} \]

Where:

  • \( P = 101325.0 \) Pa (air pressure)
  • \( R = 287.05 \) J/(kg·K) (specific gas constant for dry air)
  • \( T = 40ºC = 313.15 , K \) (convert Celsius to Kelvin)

Now calculate \( \rho \):

\[ \rho = \frac{101325.0}{287.05 \cdot 313.15} = \frac{101325.0}{8970.045} \approx 11.29 , \text{kg/m}^3 \]

Assuming typical values for \( W \), \( S \) and \( C_L \):

Let's say:

  • \( W = 100000 , \text{N} \) (approximate weight)
  • \( S = 50 , \text{m}^2 \) (typical wing area)
  • \( C_L = 1.5 \) (flaps extended)

Now substitute these values into the stall speed equation:

\[ V_{\text{stall}} = \sqrt{\frac{2 \cdot 100000}{11.29 \cdot 50 \cdot 1.5}} \ = \sqrt{\frac{200000}{11.29 \cdot 75}} \ = \sqrt{\frac{200000}{846.75}} \ = \sqrt{236.0} \approx 15.36 , \text{m/s} \]

To convert \( V_{\text{stall}} \) from m/s to knots (1 knot = 0.514444 m/s):

\[ V_{\text{stall}} \approx \frac{15.36}{0.514444} \approx 29.88 , \text{kts} \]

Part 2: Calculate the Air Flow per Engine

The airflow per engine can be calculated using:

\[ \dot{m} = \rho \cdot A \cdot V \]

Where:

  • \( \dot{m} \) = mass flow rate (kg/s)
  • \( A \) = area of the engine inlet (m²) = \( \frac{\pi D^2}{4} \)
  • \( V \) = velocity of the aircraft in m/s
  1. Calculate the inlet area (\( A \)):

\[ D = 2.96 , \text{m} \ A = \frac{\pi (2.96)^2}{4} = \frac{\pi \times 8.7616}{4} \approx 6.885 , \text{m}^2 \]

  1. Convert the True Airspeed from kts to m/s:

\[ V = 486 , \text{kts} \times 0.514444 = 249.4 , \text{m/s} \]

  1. Calculate mass flow rate (\( \dot{m} \)):

\[ \dot{m} = \rho \cdot A \cdot V \ = 11.29 \cdot 6.885 \cdot 249.4 \ \approx 11.29 \cdot 6.885 \cdot 249.4 \ \approx 1899.1 , \text{kg/s} \]

  1. Air flow per engine (assuming 2 engines):

\[ \dot{m}_{\text{per engine}} = \frac{\dot{m}}{2} \approx \frac{1899.1}{2} \approx 949.55 , \text{kg/s} \]

Part 3: Calculate the Exhaust/Jet Velocity of the Engines

Using the thrust equation:

\[ F = \dot{m} \cdot V_{e} \]

Rearranging gives:

\[ V_e = \frac{F}{\dot{m}} \]

Using the total thrust provided:

\[ F = 400,000 , \text{N} \ \dot{m} = 1899.1 , \text{kg/s} \]

\[ V_e = \frac{400000}{1899.1} \approx 210.52 , \text{m/s} \]

Part 4: Calculate Jet Efficiency

Jet efficiency (\( \eta \)) can be defined as:

\[ \eta = \frac{2 \cdot V_e}{V + V_e} \]

Substituting known values:

\[ \eta = \frac{2 \cdot 210.52}{249.4 + 210.52} \approx \frac{421.04}{459.92} \approx 0.915 , \text{or} , 91.5% \]

Thus, the answers are:

  1. Stall speed: 29.88 kts
  2. Air flow per engine: 949.55 kg/s
  3. Exhaust velocity: 210.52 m/s
  4. Jet efficiency: 91.5 (without % sign)

Feel free to ask for any clarifications or further calculations!