The air within a piston equipped with a cylinder absorbs 570J of heat and expands from an initial volume of 0.12L to a final volume of 0.88L against an external pressure of 1.0 atm. What is the change in internal energy of the air within the piston?

Answer 1

deltaE=q+w
q=570J
w=-PdeltaV
1 atm = 1.01235 x 10^5 Pa
1,000 L = 1 m^3
.76L*1.01235*10^5Pa=76938.6
that is the answer i got but it said it was wrong and idk why

Answer 2

I don't see that you used 570J anywhere. 0.76 L*atm is 77.01 J on my calculator.