Z = (score-mean)/SD
Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion/probability between the two Z scores. Multiply by 100 to get the percentage.
the ages of the members of a gym have a mean of 44 years and a standard deviation of 12 years. what can you conclude from Chebyshev's theorem about the percentage of gym members aged between 26 and 62?
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