The ages of five friends are 11, nine, 12, 10, 11, what is the main absolute deviation of the ages?

Answer 1

To find the mean absolute deviation (MAD) of the ages, we first need to find the mean age.

Mean = (11 + 9 + 12 + 10 + 11) / 5
Mean = 53 / 5
Mean = 10.6

Next, we will find the absolute deviation of each age from the mean:

|11 - 10.6| = 0.4
|9 - 10.6| = 1.6
|12 - 10.6| = 1.4
|10 - 10.6| = 0.6
|11 - 10.6| = 0.4

Now, we will find the mean of these absolute deviations:

MAD = (0.4 + 1.6 + 1.4 + 0.6 + 0.4) / 5
MAD = 4 / 5
MAD = 0.8

Therefore, the main absolute deviation of the ages is 0.8.