The ages of 3 men are in the ratio 3:4:5 if the difference between the ages of the oldest and youngest is 18 years. Find the sum of the ages of the three men.

Answer 1

Let the ages of the three men be 3x, 4x, and 5x.
We know that 5x - 3x = 18 (the difference between the ages of the oldest and youngest is 18 years).
Simplifying this, we get 2x = 18, which means x = 9.
So, the ages of the three men are 27, 36, and 45.
The sum of their ages is 27 + 36 + 45 = 108.
Therefore, the sum of the ages of the three men is 108.