the adverage weight of a blue whale is 4 x10^5 pounds the advrage weight of an elephant is 1 x10^4 pounds approximately how many times heavier is a blue whale than a elephant in pounds

Hint: You can change both of these to the number without scientific notation if that helps.

(1 point)
Responses

4 times heavier.
4 times heavier.

2 times heavier.
2 times heavier.

40 times heavier.

11 answers

To find out how many times heavier a blue whale is than an elephant, we can start by converting the weights from scientific notation to standard numbers:

  • Average weight of a blue whale: \(4 \times 10^5\) pounds = 400,000 pounds
  • Average weight of an elephant: \(1 \times 10^4\) pounds = 10,000 pounds

Next, we divide the weight of the blue whale by the weight of the elephant:

\[ \text{Times heavier} = \frac{400,000 \text{ pounds}}{10,000 \text{ pounds}} = 40 \]

Therefore, a blue whale is 40 times heavier than an elephant.

The correct response is: 40 times heavier.

(1 point)
Responses

13 x 108
13 x 108

1.3 x 10−7
1.3 x 10negative 7

13 x 10−16

It seems like you're asking for assistance in evaluating or interpreting expressions in scientific notation, but you haven't provided a specific question related to these options.

If you are evaluating which one of these is the smallest or if you need to convert them or perform some operation, please clarify what you would like to do with these numbers. Here’s a brief analysis of the numbers in their scientific notation form:

  1. \(13 \times 10^8\): This is equal to \(1.3 \times 10^9\), or 1.3 billion.

  2. \(1.3 \times 10^{-7}\): This is equal to 0.00000013 or 0.13 millionths.

  3. \(13 \times 10^{-16}\): This is equal to \(1.3 \times 10^{-15}\), which is a very small number, equal to 0.0000000000000013.

In terms of size, \(13 \times 10^{-16}\) is the smallest value, and \(13 \times 10^{8}\) would be the largest.

Please let me know how I can help you further!

what is the sum of 7 x 10^-8 and 6 x 10^-8

To find the sum of \(7 \times 10^{-8}\) and \(6 \times 10^{-8}\), you can simply add the coefficients since they are already expressed with the same exponent:

\[ 7 \times 10^{-8} + 6 \times 10^{-8} = (7 + 6) \times 10^{-8} = 13 \times 10^{-8} \]

So, the sum of \(7 \times 10^{-8}\) and \(6 \times 10^{-8}\) is:

\[ 13 \times 10^{-8} \]

the amazon river releases 5.5 x 10^7 gallons of water into the Atlantic ocean every second there are about 3 .2 x 10^7 seconds in a year how many gallons are released into the ocean in one year express your answer with the appropriate number significant digits

To find out how many gallons of water the Amazon River releases into the Atlantic Ocean in one year, we need to multiply the number of gallons released per second by the number of seconds in a year.

  1. Gallons released per second: \(5.5 \times 10^7\) gallons
  2. Seconds in a year: \(3.2 \times 10^7\) seconds

Now, we can perform the multiplication:

\[ \text{Total Gallons} = (5.5 \times 10^7) \times (3.2 \times 10^7) \]

When multiplying numbers in scientific notation, we multiply the coefficients and add the exponents:

\[ = (5.5 \times 3.2) \times (10^7 \times 10^7) \]

Calculating the coefficients:

\[ 5.5 \times 3.2 = 17.6 \]

Calculating the exponents:

\[ 10^7 \times 10^7 = 10^{(7+7)} = 10^{14} \]

Putting it all together:

\[ \text{Total Gallons} = 17.6 \times 10^{14} \]

Now, we need to express \(17.6\) in proper scientific notation with appropriate significant figures. The correct scientific notation for \(17.6\) is:

\[ 1.76 \times 10^1 \text{ (since we shift the decimal point left one place)} \]

Thus, we have:

\[ 1.76 \times 10^1 \times 10^{14} = 1.76 \times 10^{15} \]

Finally, expressing our answer with the appropriate significant digits (the least number of significant digits from the initial values is 2, from \(3.2 \times 10^7\)) gives us:

\[ \text{Total Gallons} \approx 1.8 \times 10^{15} \text{ gallons} \]

So, the Amazon River releases approximately \(1.8 \times 10^{15}\) gallons of water into the Atlantic Ocean in one year.

(1 point)
Responses
calculate the value of the expression 35 / 5 . 7 - 2^3
-7
-7

-1
-1

7
7

41

To calculate the value of the expression \( 35 / 5 + 7 - 2^3\), we will follow the order of operations (PEMDAS/BODMAS: Parentheses, Exponents, Multiplication and Division (from left to right), Addition and Subtraction (from left to right)):

  1. Calculate the division: \[ 35 / 5 = 7 \]

  2. Calculate the exponent: \[ 2^3 = 8 \]

  3. Plugging these values back into the expression: \[ 7 + 7 - 8 \]

  4. Perform addition: \[ 7 + 7 = 14 \]

  5. Perform subtraction: \[ 14 - 8 = 6 \]

Since none of the provided responses match the calculated value of \(6\), I may have misunderstood the expression originally or misrepresented it.

However, if the original expression you meant was \(35 / 5 - 7 - 2^3\), let's calculate that:

  1. Calculate \(35 / 5\): \[ 35 / 5 = 7 \]

  2. Calculate \(2^3\): \[ 2^3 = 8 \]

  3. Plug these values into the expression: \[ 7 - 7 - 8 \]

  4. Perform the first subtraction: \[ 7 - 7 = 0 \]

  5. Perform the second subtraction: \[ 0 - 8 = -8 \]

In this case, neither option matches, so if you meant this expression as stated at the start (\(35/5 + 7 - 2^3\)), the result is \(6\).

If you'd like further clarification or if there was an error in the original expression provided, please let me know!

35 divided by 5 ' 7 - 2^3

It looks like there might have been a bit of confusion with the expression you provided. Let’s clarify it step by step.

The expression "35 divided by 5, then 7 minus 2 cubed" can be interpreted mathematically as:

\[ \frac{35}{5} + 7 - 2^3 \]

Let's break it down step by step:

  1. Calculate \(35 / 5\): \[ 35 / 5 = 7 \]

  2. Calculate \(2^3\): \[ 2^3 = 8 \]

  3. Now substitute these values back into the expression: \[ 7 + 7 - 8 \]

  4. Perform the addition: \[ 7 + 7 = 14 \]

  5. Perform the subtraction: \[ 14 - 8 = 6 \]

So, if interpreted this way, the value of the expression is \(6\).

If instead, the expression means something else (for example, if you meant \(35 \div 5 \cdot 7 - 2^3\) or any other arrangement), please clarify the intended operations, and I'll be happy to assist!