each mole of air 28.98 grams, in 22.4L
22.4L/28.98g=5e3L/xx
xx= 28.98g*5e3/22.4=6468grams= 6.5kg
The adult blue whale has a lung capacity of 5.0 x 10^3L. Calculate the mass of air (assume an average molar mass of 28.98g/mol) contained in an adult blue whales lungs at 0.0 Celsius and 1.00atm, assuming the air behaves ideally.
I have the answer but don’t know how to get it :(
Answer is 6.5kg air
2 answers
the first answer wrong its 7.1g