the actual problem is integral(2 to +infinity) (1/x^2) dx
and after integrating and plugging in the bounds, i got
-1/(infinity sign)+ 1/2
does that converge to 1/2, Ln2, 1, 2 or is the answer nonexistent?
what i was thinking that everytime the bottom number increases seeing the number in infinity, the answer decreases so adding the 1/2 will make a difference but i don't know what it will converge to.
1/infinity = 0, so the answer is 1/2
You evaluated the integral correctly