The acceleration of a particle is defined by the relation a = -k/x . It has been experimentally determined that v = 15 ft/s when x = 0.6 ft and that v = 9 ft/s when x = 1.2 ft. determine (a) the velocity of the particle when x = 1.5 ft and (b) the position of the particle at which its velocity is zero.

Answer 1

v = -k ln x + c

15 = -k ln .6 + c
9 = -k ln 1.2+ c
-----------------subtract
6 = -k ln(.6/1.2)
etc