The acceleration due to gravity on the moon is 1.62 m/s2. What is the length of a pendulum whose period on the moon matches the period of a 4.50-m-long pendulum on earth

Answer 1

For the same period, sqrt(l/g) must be the same. With 1/6 the value of g on the moon,
compared to Earth, you will need 1/6 the pendulum length to match the periods.