The acceleration due to gravity on the moon is 1.62 m/s2. What is the length of a pendulum whose period on the moon matches the period of a 4.50-m-long pendulum on earth

Answer 1

T^2 = 4(pi)^2 * (L/g).

L2 = (g2/g1)L1 = (1.62/9.8)4.5=0.74m.