For a given launch velocity, it takes 6 times as long for the object to reach maximum height on the moon, and that height will be six times higher.
(ascent time) = (Initial velocity)/(deceleration rate)
max height = (average velocity) x (ascent time)
The acceleration due to gravity on the Moon is 1/6 of that of the Earth. Given the same initial velocity:
How much higher will an object displace on the Moon?
How much more time will it spend in the air?
1 answer
1 answer