a = 25 - 9t^2
v = 25t - 3t^3 + c
v(0) = 4, so c=4 and
v = 25t - 3t^3 + 4
now just find v(2)
The acceleration, ams^-2, of a particle is given by a =25 – 9t^2, where t is in seconds after the particle passes fixed point O. If the particle passes O, with velocity of 4 ms^-1, find
(a) An expression for velocity V, in terms of t
(b) The velocity of the particle when t = 2
1 answer
1 answer