9th term = a+8d
5th term = a + 4d
given: 9th term = 3(5th term)
a + 8d = 3(a + 4d)
a + 8d = 3a + 12d
-2a = 4d
a = -2d, where a is the first term
The 9th term of an arithmetic progression is three times the 5th term, find the relationship between the first term and common difference
2 answers
Do we need to solve for difference
(d)
(d)
2 answers