The 8th term of linear sequence is 18 and the 12th term is 26.find the first term, the common difference and the 20th term
2 answers
Pls I want solution to the question
d = (26-18)/(12-8) = ____
now you have d, so
a = 18 - 7d
Now you have a and d, so
a20 = a+19d
Of course, you don's need a and d to find a20
since the 20th term is 8 terms past the 12 term, which is 4 terms past the 8th term, it is twice as far from a12 as a12 is from a8.
a20 = 26 + 2(26-18) = ____
now you have d, so
a = 18 - 7d
Now you have a and d, so
a20 = a+19d
Of course, you don's need a and d to find a20
since the 20th term is 8 terms past the 12 term, which is 4 terms past the 8th term, it is twice as far from a12 as a12 is from a8.
a20 = 26 + 2(26-18) = ____
2 answers