well, you have
a+42(1/2) = 26
a+21 = 26
a = 5
The 43rd of an AP is 26 find the first term of progression given that the common difference is 1/2
8 answers
the sun infinity of a geometric progression(g.p) if first term of series is12
How did you get 21
ARITHMETIC
the 43 ap of 26 find the first term with common different of halp
A +42(1/2)=26
A +21=26
A=26-21
A=5
A +21=26
A=26-21
A=5
A=5
Tn=a+(n-1)d=26
T43=a+(43-1)1/2=26
a+(42)×1/2=26
a+21=26
a=26-21
=5
T43=a+(43-1)1/2=26
a+(42)×1/2=26
a+21=26
a=26-21
=5