Since each roll of the die is independent of the other roll, the probability of rolling a 1 and a 4 in any order is the same as the probability of rolling a 1 on the first roll and a 4 on the second roll, or vice versa.
The probability of rolling a 1 on the first roll is 1/4, and the probability of rolling a 4 on the second roll is also 1/4. So, the probability of rolling a 1 and a 4 in any order is (1/4) * (1/4) = 1/16.
Therefore, out of 360 repetitions of the experiment, we can expect 360 * 1/16 = 22.5 times that the result will be a 1 and a 4 in any order. Since you cannot have a fraction of a result, we can predict that this will occur approximately 23 times in 360 repetitions.
The 4-sided die, labeled 1–4, is rolled twice.
If you repeat this experiment 360 times, how many times do you predict that the result will be a 1 and a 4 in any order?
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