there are 6 terms between 54 and 39336, so
r^6 = 39336/54 = 6556/9
I suspect a typo, since it is not rational.
Anyway, use that or fix it, and you will have r.
Then a = 54/r^2
Having a and r, you can find any other terms.
"sum of 4th term" makes no sense.
The 3rd and 9th term of a g.p are 54 and 39,336 respectively.find the 6th term,sum of 4th term,sum of 4th and 7th term and product of 2nd and 5th term
6 answers
"3rd and 9th term of a g.p are 54 and 39,336"
--> ar^2 = 54 and ar^8 = 39336
ar^8/(ar^2) = 39336/54
r^6 = 728.444.. , I suspect that was supposed to be 729 , since 3^6 = 729
I will go with r = ± 3
then in ar^2 = 54
9a = 54 , ----> a = 6
so your typo was in 9th term is 39366 instead of your 39336
take the rest from there
--> ar^2 = 54 and ar^8 = 39336
ar^8/(ar^2) = 39336/54
r^6 = 728.444.. , I suspect that was supposed to be 729 , since 3^6 = 729
I will go with r = ± 3
then in ar^2 = 54
9a = 54 , ----> a = 6
so your typo was in 9th term is 39366 instead of your 39336
take the rest from there
the 3rd and 9th term of a gp are 54 and 39366 respectively. find the 6th term
I need the answer
The 3rd and 9th term of a GP are 54 and 39366. Respectively find the following (a) 6th term (b)sum of the 4th and 7th terms (c) product of the 2nd and 5th terms.
The third and the nineth terms of a GP are 54and 39366 respectively. Find the sixth terms and the sum of the 4th term and the sum of infinity
1 answer