Asked by Kamath
The 2nd question has a fraction and I think this is confusing me on this one
f(x)=1/5(x+7)^2+7
I need to find the vertex line of symmetry max/min and is the value f(-7)=7 a minimum or a maximum?
f(x)=1/5(x+7)^2+7
I need to find the vertex line of symmetry max/min and is the value f(-7)=7 a minimum or a maximum?
Answers
Answered by
Damon
You typed that so I am not sure what you mean.
y = (1/5) (x+7)^2 + 7
or
y = 1/[5(x+7)^2] + 7
I will assume the first.
then
(y-7) = (1/5)(x+7)^2
when x = -7 (the axis of symmetry), the right is zero so y = 7
as x gets big or very negative, y gets big so parabola faces up (holds water).
Therefore the vertex at (-7,7) is a minimum
y = (1/5) (x+7)^2 + 7
or
y = 1/[5(x+7)^2] + 7
I will assume the first.
then
(y-7) = (1/5)(x+7)^2
when x = -7 (the axis of symmetry), the right is zero so y = 7
as x gets big or very negative, y gets big so parabola faces up (holds water).
Therefore the vertex at (-7,7) is a minimum
Answered by
Kamath
Thanks so much I just looked at my answers and I realized I had gotten the right answers after all. Many thanks
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