The 22 students present for a recent test in Ms. Huang’s class had an average score of 88. When students who were absent took the test, three scored 4 points higher than the average and two scored one point higher than the average. What is the new class average when the new scores are included?

Answer 1

total points scored: 22*88 = 1936
Now we add 5 scores, increasing the total by 3*92 + 2*89 = 454

So, the new average for 27 students is

(1936+454)/(22+5) = 88.52