The 19th and 22nd term of an AP are 29 and 55 respectively. find the sum of the 60th term

Answer 1

the 19th and 22nd terms differ by 3d.
So, d=(55-29)/3 = 8
Now you can find a
Not sure what the sum of the 60th term means, but the sum of the first 60 terms is
s = 60/2 (2a+59d)

Answer 2

a + 18d = 29
a + 21d =55
subtract:
3d = 26
d = 26/3
a + 18(26/3) = 29
a = -127

"find the sum of the 60th term" makes no sense
Do you want the 60th term of the sum of the first 60 terms?

either way, just plug in the values of a and d into the formulas

Answer 3

go with Reiny. I assumed an integer value for d, and missed the fact that 55-29=26, not 24.

Answer 4

I Kc jlk

Answer 5

26