The 1994 Winter Olympics included the aerials competition in skiing. In this event skiers speed down a ramp that slopes sharply upward at the end. The sharp upward slope launches them into the air, where they perform acrobatic maneuvers. In the women's competition, the end of a typical launch ramp is directed 68° above the horizontal. With this launch angle, a skier attains a height of 14 m above the end of the ramp. What is the skier's launch speed?

asked by Donald

12 years ago

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1 answer

max height with velocity v is

h = v^2 sin^2 θ/2g
14*2*9.8 = .86 v^2
v = 17.8 m/s

answered by Steve

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Question

The 1994 Winter Olympics included the aerials competition in skiing. In this event skiers speed down a ramp that slopes sharply upward at the end. The sharp upward slope launches them into the air, where they perform acrobatic maneuvers. In the women's competition, the end of a typical launch ramp is directed 68° above the horizontal. With this launch angle, a skier attains a height of 14 m above the end of the ramp. What is the skier's launch speed?

1 answer

max height with velocity v is

h = v^2 sin^2 θ/2g
14*2*9.8 = .86 v^2
v = 17.8 m/s

Ask a New Question or answer this question.

Steve · Answer

max height with velocity v is h = v^2 sin^2 θ/2g 14*2*9.8 = .86 v^2 v = 17.8 m/s