The 1800 kg tractor exerts a force of 1.75 104 N backward on the pavement, and the system experiences forces resisting motion that total 2400 N. If the acceleration is 0.210 m/s2, what is the mass of the airplane?

Question

(b) Calculate the force exerted by the tractor on the airplane, assuming 2100 N of the friction is experienced by the airplane.

Answer 1

Fap = 17,500 N. = Force applied.
Fk = 2400 N. = Force of kinetic friction

a. m=(Fap-Fk)/a
m = (17,500-2400)/0.21=71,905 kg.

Answer 2

b. Fap-2100 = m*a
Fap-2100 = 71,905*0.21
Fap-2100 = 15,100
Fap = 17,200 N.