The 14th term of an A.P is 96,while 25th term is 173 find the ,19th term,sum of 13th and 56th terms,product of 6th and 13th terms.

Answer 1

You are just using the standard definitions here:

14th term --> a + 13d = 96
25th term --> a + 24d = 173
subtract them:
11d = 77
d = 7
back in a + 13d = 96
a + 91 = 96
a = 5

Now you can find any term, e.g.
19th term = a + 18d
= 5 + 18(7) = 131

once you have the terms involved just do the operations asked for

Answer 2

Sn=n/2(2a+(n-1)d)
S56=56/2(2x5+(56-1)x7)
......=28(10+55x7)
...... =28(395)
........ =11060
S56=11060

Answer 3

The 19th term

Answer 4

Thanks

Answer 5

Fantastic

Answer 6

Wonderful

Answer 7

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