I have never heard of the term "quotient function". From your description of what it is,I would suggest that you just compute f(x) and g(x) for the x value you are given, and take the ratio.
f(-1/2) = -3 1/4
g(-1/2) = 0
f/g (-1/2) = infinity
The "quotient function" is just f(x)/g(x), which you can write as a ratio of the two functions
That is not what the ? is asking. The ? is asking about how to get the quotient function, not the composite as you solved for. Can you please show us how to get the quotient function solution? Thanks!
I need to find the Quotient Function of the following:
Given that f(x)=x^2-3 and g(x)=2x+1 find each of the following if it exists:
a. (f/g)(-root3)
b. (g/f)(-1/2)
5 answers
What about A? Is there a solution for it?
Given that f(x)=x^2-3 and g(x)=2x+1 find each of the following if it exists:
a. (f/g)(-root3)
Given that f(x)=x^2-3 and g(x)=2x+1 find each of the following if it exists:
a. (f/g)(-root3)
Did you combine the two problems? These are two separate functions.
I need to find the Quotient Function of the following:
Given that f(x)=x^2-3 and g(x)=2x+1 find each of the following if it exists:
a. (f/g)(-root3)
b. (g/f)(-1/2)
I need to find the Quotient Function of the following:
Given that f(x)=x^2-3 and g(x)=2x+1 find each of the following if it exists:
a. (f/g)(-root3)
b. (g/f)(-1/2)
f/g is (x^2 -3)/(2x+1)
Plug in -sqrt3 for x and compute
g/f is (2x+1)/(x^2 -3)
Plug in -1/2 for x and compute
Plug in -sqrt3 for x and compute
g/f is (2x+1)/(x^2 -3)
Plug in -1/2 for x and compute
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