If your equation is written in the form
(x-h)^2 + (y-k)^2 = r^2 , the centre is (h,k) and the radius is r
Your equation is written in that form and the centre and radius can be seen as is.
Let me know what you got.
Thank you for your help! The question is what is the center and radius of the circle. (x+2)^2+y^2=64. Thank you so much.
3 answers
Yup. That is what I got reiny. :) Thanks again.
ok, so my final answer is h=2, k=0, r^2=64, then r=8, is this right?