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Test score are normally distributed with a mean of 500 and a standard deviation of 50. What percentage of students scored below a 575?

a
93.32%
b
50%
c
56.68%
d
6.68%

2 answers

Z = (score-mean)/SD = (575-500)/50 = 75/50 = 1.5

Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion/probability related to the Z score.
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david lane normal distribution