Teri, nick, and Alex had $865 altogether. Teri spent 2/5 of her money. Nick spent $40, and Alex spent twice as much as Alex. If the three friends had the same amount of money left, how much money did Alex have in the beginning?

Answer 1

Looking at all the "Related Questions" below, you must have a typo.
Most say "Alex spent twice as much as Terry"

let Terry's amount be x
let Nick's amount be y
let Alex' amount be 865-x-y

after the spending:
Terry has (3/5)x = 3x/5
Nick has y-40

Terry spend 2x/5
so Alex spent 4x/5
and Alex has left 865-x-y - 4x/5
= (4325-5x-5y - 4x)/5
= (4325 - 9x - 5y)/5

all have the same amount left over ...
3x/5 = y-40
3x= 5y - 200
3x - 5y = -200 , #1

(4325 - 9x - 5y)/5 = y-40
4325 - 9x - 5y = 5y - 200
9x + 10y = 4525 , #2

#1 times 2
6x - 10y = -400
9x - 10y = 4525
add them ...
15x = 4125
x = 275
then in #1:
3(275) - 5y = -200
y = 205

Terry had 275
Nick had 205
Alex had 865-275-200 = 385

check:
Terry has (3/5)275 or 165 left
Nick has 205-40 or 165 left
Terry spent (2/5)(275) or 110, so
Alex spent 220
leaving him with 385-220 = 165
ALL LOOKS GOOD

Answer 2

itz 2/5 for Teri so you didyour math wrong

Answer 3

Nevermind you're fine