Teresa is maintaining a camp fire. She can keep the fire burning for 4 hours with 6 logs. She wants to know how many logs (y) she needs to keep the fire burning for 18 hours. She assumes all logs are the same.

Question

How many logs does Teresa need to maintain the fire for 18 hours?

Answer 1

We can set up a proportion to find the number of logs needed:
4 hours/6 logs = 18 hours/y logs

Cross-multiplying, we get:
4y = 18 * 6

Simplifying the right side, we get:
4y = 108

Dividing both sides by 4, we find:
y = 27

Therefore, Teresa needs 27 logs to maintain the fire for 18 hours. Answer: \boxed{27}.