i did 26 *26*9 because there are 26 letters in an alphabet, and just 1 letter can go into 26 (counting its self) and 9 because it has to be 1 number.
so 26*26*9=6084
teresa has to create a password that contains 1 digit and 2 letters. find the number of possible passwords?
how do you do this?
2 answers
I will assume that zero can be used as a digit, and that letters can repeat.
There are 3 ways for the digit and letters to show up
DLL
LDL
LLD
let's find the number of ways DLL can be done
= 10x26x26
the same with the other two, so the number of ways is
3(10)(26)(26) = 20280
There are 3 ways for the digit and letters to show up
DLL
LDL
LLD
let's find the number of ways DLL can be done
= 10x26x26
the same with the other two, so the number of ways is
3(10)(26)(26) = 20280
1 answer