To find out how much less time Lamar took compared to Teresa, we need to subtract Lamar's time from Teresa's time.
Teresa's time: \( \frac{3}{4} \) hour
Lamar's time: \( \frac{2}{3} \) hour
First, we need a common denominator to perform the subtraction. The least common multiple of 4 and 3 is 12.
Now convert both times to have a denominator of 12:
-
Teresa's time:
\[ \frac{3}{4} = \frac{3 \times 3}{4 \times 3} = \frac{9}{12} \] -
Lamar's time:
\[ \frac{2}{3} = \frac{2 \times 4}{3 \times 4} = \frac{8}{12} \]
Now we can subtract Lamar's time from Teresa's time:
\[ \frac{9}{12} - \frac{8}{12} = \frac{1}{12} \]
Thus, Lamar finished his test in \( \frac{1}{12} \) hour less than Teresa.
The answer is \( \text{D. } \frac{1}{12} \text{ hour less} \).