Balin's expression to find the distance that each member ran is \(\frac{5}{6} \div 10\).
To find an equivalent expression, we can make use of the properties of division and multiplication:
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The expression \(\frac{5}{6} \div 10\) can be rewritten as \(\frac{5}{6} \times \frac{1}{10}\).
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This further simplifies to \(\frac{5}{60}\), which is \(\frac{1}{12}\).
Now let's analyze the options to see which one is equivalent to \(\frac{5}{6} \div 10\):
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\(\frac{10}{12} \div 10\) simplifies to \(\frac{10}{120} = \frac{1}{12}\) (equivalent).
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\(\frac{10}{6} \div 5\) simplifies to \(\frac{10}{30} = \frac{1}{3}\) (not equivalent).
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\(\frac{6}{5} \times 10\) simplifies to \(\frac{60}{5} = 12\) (not equivalent).
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\(\frac{5}{6} \times 10\) simplifies to \(\frac{50}{6} = \frac{25}{3}\) (not equivalent).
Thus, the expression that is equivalent to Balin’s expression is:
\(\frac{10}{12} \div 10\).