Ten less than twice a number is equal to at most 52. What are all the possible values of the number? Inuk wrote the inequality 2x−10≤52

Question

, where x
equals the number, to help solve this problem. Solve his inequality. Use the letter x
as your variable and write your x
term first.

Note: You will find the option to add a >
, <
, ≥
, or ≤
symbol in the Comparison (<)
keyboard.

(1 point).

Answer 1

To solve the inequality \( 2x - 10 \leq 52 \), we will first isolate \( x \).

1. Add 10 to both sides: \[ 2x - 10 + 10 \leq 52 + 10 \] \[ 2x \leq 62 \]

2. Divide both sides by 2: \[ \frac{2x}{2} \leq \frac{62}{2} \] \[ x \leq 31 \]

So the solution to the inequality \( 2x - 10 \leq 52 \) is: \[ x \leq 31 \]

This means that the possible values of the number \( x \) can be any value that is less than or equal to 31.