Ten less than twice a number is equal to at most 52. What are all the possible values of the number? lnuk write the ineuality 2x - 10 _< 52 where x equals the number to help this problem solve his inequality Use the letter as ur variable and write ur x term first

Answer 1

Let's denote the number as \( x \). According to the problem statement, ten less than twice a number is equal to at most 52. This can be expressed with the following inequality:

\[ 2x - 10 \leq 52 \]

Now, let's solve this inequality step by step:

1. Add 10 to both sides: \[ 2x - 10 + 10 \leq 52 + 10 \] Which simplifies to: \[ 2x \leq 62 \]

2. Divide both sides by 2: \[ \frac{2x}{2} \leq \frac{62}{2} \] This simplifies to: \[ x \leq 31 \]

Therefore, the possible values of the number \( x \) are all numbers that are less than or equal to 31. In interval notation, this can be expressed as:

\[ (-\infty, 31] \]

So, the final answer is that \( x \) can be any number less than or equal to 31.