Question

Ten less than twice a number is equal to at most 52. What are all the possible values of the number? lnuk write the ineuality 2x - 10 _< 52 where x equals the number to help this problem solve his inequality Use the letter as ur variable and write ur x term first

Answer 1

Let's denote the number as \( x \). According to the problem statement, ten less than twice a number is equal to at most 52. This can be expressed with the following inequality:

\[
2x - 10 \leq 52
\]

Now, let's solve this inequality step by step:

1. **Add 10 to both sides**:
\[
2x - 10 + 10 \leq 52 + 10
\]
Which simplifies to:
\[
2x \leq 62
\]

2. **Divide both sides by 2**:
\[
\frac{2x}{2} \leq \frac{62}{2}
\]
This simplifies to:
\[
x \leq 31
\]

Therefore, the possible values of the number \( x \) are all numbers that are less than or equal to 31. In interval notation, this can be expressed as:

\[
(-\infty, 31]
\]

So, the final answer is that \( x \) can be any number less than or equal to 31.