To solve the inequality 2x-10 ≤ 52, we can isolate the variable x:
2x - 10 ≤ 52
2x ≤ 62
x ≤ 31
Therefore, the possible values of the number (x) are any number less than or equal to 31.
Ten less than twice a number is equal to at most 52. What are all the possible values of the number? Inuk wrote the inequality 2x−10≤52, where x equals the number, to help solve this problem. Solve his inequality. Use the letter x as your variable and write your x term first. X is less than or equal to is not the answer
5 answers
Wrong
Apologies for the incorrect response in the previous message. Let's solve the inequality correctly.
The inequality given is 2x - 10 ≤ 52.
To isolate x, we'll undo the subtraction and multiplication:
2x - 10 + 10 ≤ 52 + 10
2x ≤ 62
Lastly, we divide both sides of the inequality by 2:
2x/2 ≤ 62/2
x ≤ 31
Therefore, the possible values of the number x are any number less than or equal to 31.
The inequality given is 2x - 10 ≤ 52.
To isolate x, we'll undo the subtraction and multiplication:
2x - 10 + 10 ≤ 52 + 10
2x ≤ 62
Lastly, we divide both sides of the inequality by 2:
2x/2 ≤ 62/2
x ≤ 31
Therefore, the possible values of the number x are any number less than or equal to 31.
Its not x ≤ 31, still wrong
Apologies again for the mistake. Let's correct our solution.
To solve the inequality 2x - 10 ≤ 52, we will isolate the variable x:
2x - 10 ≤ 52
First, we add 10 to both sides of the inequality:
2x - 10 + 10 ≤ 52 + 10
2x ≤ 62
Next, we divide both sides of the inequality by 2:
(2x)/2 ≤ 62/2
x ≤ 31
The correct answer is x ≤ 31.
This means that all values of x which are less than or equal to 31 satisfy the inequality.
To solve the inequality 2x - 10 ≤ 52, we will isolate the variable x:
2x - 10 ≤ 52
First, we add 10 to both sides of the inequality:
2x - 10 + 10 ≤ 52 + 10
2x ≤ 62
Next, we divide both sides of the inequality by 2:
(2x)/2 ≤ 62/2
x ≤ 31
The correct answer is x ≤ 31.
This means that all values of x which are less than or equal to 31 satisfy the inequality.
1 answer