change in dB = 10 log base ten (intensity ratio)
= 10 log (100)
= 10*2
= 20 db for ten times intensity
so 80 dB each
Ten cars at an intersection are blowing their horns simultaneously, creating a 100 decibel sound in the middle of the intersection. What is the average sound level for each car?
10/100= 10db per car?? Idk
2 answers
Just TEN cars
10 log 10 = 10
so ten dB for 10 times intensity
so
90 db each
10 log 10 = 10
so ten dB for 10 times intensity
so
90 db each